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5+21x^2-22x=0
a = 21; b = -22; c = +5;
Δ = b2-4ac
Δ = -222-4·21·5
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-8}{2*21}=\frac{14}{42} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+8}{2*21}=\frac{30}{42} =5/7 $
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